Let \( n \) be a positive integer. Explain why
\[
\binom{n}{0} + \binom{n}{1} + \binom{n}{2} + \dots + \binom{n}{n} = 2^n.
\]
combinatoricsbinomial-coefficientscombinatorial-proofbit-stringssum-of-binomial-coefficientsdiscrete-mathematicscountingsubsetscombinationsmultiplication-principleidentity-proofpascal-triangle-row-sum
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